Electrolysis of Aqueous Solutions

Summary: In aqueous electrolysis, the ions discharged depend on the reactivity series and concentration. Water can be oxidized/reduced in competition with dissolved ions. The ion that is discharged at each electrode is the one that is most easily gained/lost. Tags: igcse chemistry electrolysis Created: 2026-07-14 Last Updated: 2026-07-16


Learning Objectives

By the end of this topic, you should be able to:

  • Predict the products at the cathode and anode for any given aqueous solution
  • Apply the rules for ion competition at electrodes (reactivity series for cations, halide/OH- for anions)
  • Write half-equations for reactions at both electrodes
  • Explain how concentration affects which ion is discharged (concentrated vs dilute)
  • Describe observations for common electrolysis reactions (gas production, colour changes, metal deposition)

Content

1. How Aqueous Electrolysis Differs from Molten Electrolysis

In molten electrolysis, there is only one cation and one anion present — the products are predictable. In aqueous electrolysis, water dissociates slightly:

H2O(l) ⇌ H+(aq) + OH-(aq)

This means four ions are present in the electrolyte:

  • From the solute: the cation (e.g., Na+) and anion (e.g., Cl-)
  • From water: H+ and OH-

2. Rules for Predicting Electrode Products

At the Cathode (Negative Electrode) — Reduction Occurs

Cations compete to gain electrons. The rule depends on the reactivity series:

Cation PositionDischarged at Cathode?Product
K+, Na+, Ca2+, Mg2+, Al3+ (highly reactive metals)NO — H+ from water is discharged insteadHydrogen gas (H2)
Zn2+, Fe2+, Sn2+, Pb2+ (moderately reactive)Sometimes (depends on conditions)Metal or H2
Cu2+, Ag+, Au+ (low reactivity)YES — the metal ion is dischargedMetal deposited

Key rule: The less reactive the metal, the more easily its ions are reduced. H+ is easier to discharge than reactive metal ions (K+, Na+, Ca2+, Mg2+, Al3+), so hydrogen is produced at the cathode when these reactive metals are in solution.

At the Anode (Positive Electrode) — Oxidation Occurs

Anions compete to lose electrons. The rule depends on the type of anion:

Anion PresentDischarged at Anode?Product
Cl-, Br-, I- (halides)YES in concentrated solutionHalogen gas (Cl2, Br2, I2)
Cl-, Br-, I- (halides)Maybe (competes with OH-) in dilute solutionHalogen gas or O2
SO4 2-, NO3 -, CO3 2-, F- (all others)NO — OH- from water is discharged insteadOxygen gas (O2)

Key rule: If a halide ion is present, it tends to be discharged. If not, OH- is discharged producing oxygen. In dilute halide solutions, OH- can compete and produce oxygen instead.

3. The Effect of Concentration

Concentrated solutions of halides favour the discharge of the halide ion at the anode:

  • Concentrated NaCl(aq): Cl- discharged → chlorine gas at anode
  • Dilute NaCl(aq): OH- may be discharged instead → oxygen gas at anode

This is because concentration affects the position of ion competition — a higher concentration of a particular ion makes it more likely to be discharged.

4. Half-Equations for Common Electrode Reactions

Cathode Half-Equations (Reduction — gain of electrons)

ProductHalf-Equation
Hydrogen gas2H+ + 2e- → H2(g)
Copper metalCu2+ + 2e- → Cu(s)
Sodium metal (molten only)Na+ + e- → Na(s)

Anode Half-Equations (Oxidation — loss of electrons)

ProductHalf-Equation
Chlorine gas2Cl- → Cl2(g) + 2e-
Bromine liquid2Br- → Br2(l) + 2e-
Iodine solid2I- → I2(s) + 2e-
Oxygen gas4OH- → O2(g) + 2H2O(l) + 4e-

Exam tip: The oxygen half-equation at the anode (4OH- → O2 + 2H2O + 4e-) is frequently tested. Memorise it exactly.

5. Specific Examples

Example 1: Electrolysis of Concentrated NaCl(aq) — Brine

FeatureDetail
Ions presentNa+, Cl-, H+, OH-
At Cathode (-)H+ discharged (Na+ too reactive) → H2 gas (bubbles, ‘pop’ with lit splint)
At Anode (+)Cl- discharged (concentrated) → Cl2 gas (yellow-green, bleaches litmus)
Ions left in solutionNa+ and OH- → sodium hydroxide (NaOH) formed

Overall: 2NaCl(aq) + 2H2O(l) → H2(g) + Cl2(g) + 2NaOH(aq)

Example 2: Electrolysis of CuSO4(aq) with Inert Electrodes

FeatureDetail
Ions presentCu2+, SO4 2-, H+, OH-
At Cathode (-)Cu2+ discharged (low reactivity) → Copper metal deposited (pink/brown solid)
At Anode (+)OH- discharged (SO4 2- is not discharged) → O2 gas (relights glowing splint)
ObservationBlue colour of solution fades as Cu2+ ions are removed; cathode gains brown deposit

Cathode: Cu2+ + 2e- → Cu(s) Anode: 4OH- → O2(g) + 2H2O(l) + 4e-

Example 3: Electrolysis of CuSO4(aq) with Copper Electrodes

This is copper refining (not a typical aqueous electrolysis question but related):

  • Cathode: Cu2+ + 2e- → Cu(s) (pure copper plates onto cathode)
  • Anode: Cu(s) → Cu2+ + 2e- (impure copper anode dissolves)
  • Impurities fall to the bottom as anode sludge

Example 4: Electrolysis of Dilute H2SO4(aq)

FeatureDetail
Ions presentH+, SO4 2-, H+, OH- (essentially H+ and OH- / SO4 2-)
At Cathode (-)H+ discharged → H2 gas
At Anode (+)OH- discharged (SO4 2- not discharged) → O2 gas
Net resultElectrolysis of water: 2H2O(l) → 2H2(g) + O2(g)
Volume ratio2 volumes H2 : 1 volume O2 (H2 collected at cathode, O2 at anode)

Example 5: Electrolysis of NaOH(aq)

FeatureDetail
Ions presentNa+, OH-, H+, OH-
At Cathode (-)H+ discharged (Na+ too reactive) → H2 gas
At Anode (+)OH- discharged → O2 gas
Net resultElectrolysis of water — NaOH concentration increases, water is decomposed

Example 6: Electrolysis of KI(aq)

FeatureDetail
Ions presentK+, I-, H+, OH-
At Cathode (-)H+ discharged (K+ too reactive) → H2 gas
At Anode (+)I- discharged (halide) → I2 solid (brown/black solid or brown solution)

6. Observations Summary Table

SolutionCathode ProductCathode ObservationAnode ProductAnode Observation
NaCl(aq) conc.H2Colourless gas, ‘pop’Cl2Yellow-green gas, bleaches litmus
CuSO4(aq)CuPink/brown solid depositedO2Colourless gas, relights splint
H2SO4(aq) diluteH2Colourless gas, ‘pop’O2Colourless gas, relights splint
NaOH(aq)H2Colourless gas, ‘pop’O2Colourless gas, relights splint
KI(aq)H2Colourless gas, ‘pop’I2Brown/black solid formed

Worked Examples (Exam-Style)

Example 1: Predicting Products

Question: What are the products at each electrode during the electrolysis of concentrated aqueous sodium chloride using inert electrodes? Explain your answer. [4 marks]

Solution:

  • At the cathode: Hydrogen gas (H2) ✓ — Na+ is above hydrogen in the reactivity series, so H+ from water is preferentially discharged ✓
  • At the anode: Chlorine gas (Cl2) ✓ — Cl- is a halide ion (present in concentrated solution), so it is preferentially discharged over OH- ✓

Example 2: Half-Equations

Question: Write the half-equations for the electrolysis of aqueous copper(II) sulfate using inert electrodes. [2 marks]

Solution:

  • Cathode: Cu2+ + 2e- → Cu ✓
  • Anode: 4OH- → O2 + 2H2O + 4e- ✓

Practice Questions

  1. Name the products formed at the cathode and anode when concentrated aqueous sodium chloride is electrolysed using inert electrodes. [2 marks]

  2. Explain why hydrogen, and not sodium, is produced at the cathode during the electrolysis of aqueous sodium chloride. [2 marks]

  3. Write the half-equation for the reaction at the anode when aqueous copper(II) sulfate is electrolysed using inert electrodes. [1 mark]

  4. A student electrolyses dilute sulfuric acid. Name the gas produced at each electrode and state the volume ratio in which they are collected. [3 marks]

  5. Describe what would be observed at each electrode when aqueous potassium iodide is electrolysed using inert electrodes. [4 marks]


Key Facts to Memorise

  • Cathode (negative): reduction (gain of electrons). Anode (positive): oxidation (loss of electrons)
  • Reactive metal ions (K+, Na+, Ca2+, Mg2+, Al3+) are NOT discharged in aqueous solution — H+ is discharged instead producing H2
  • Less reactive metal ions (Cu2+, Ag+) ARE discharged — metal deposited
  • Halide ions (Cl-, Br-, I-) are discharged at anode → halogen produced (especially in concentrated solutions)
  • All other anions (SO4 2-, NO3 -, CO3 2-) are NOT discharged — OH- is discharged instead producing O2
  • Oxygen half-equation: 4OH- → O2 + 2H2O + 4e-
  • Electrolysis of dilute H2SO4 = electrolysis of water: 2H2 : 1O2 volume ratio

Common Misconceptions

Students often think…But the correct understanding is…
”Sodium metal is produced at the cathode when NaCl(aq) is electrolysed”H2 is produced because H+ is easier to reduce than Na+ in aqueous solution. Sodium is only produced from MOLTEN NaCl
”SO4 2- is discharged at the anode producing SO2 or SO3”SO4 2- is NOT discharged. OH- from water is oxidised instead, producing O2 gas
”All halides are always discharged at the anode”In very dilute solutions, OH- can compete and be discharged instead, producing O2
”The same products are always obtained regardless of concentration”Concentration matters for halide solutions — concentrated favours halogen, dilute may give oxygen

Key Concepts from Past Papers

Definitions You MUST Know (Exact Mark Scheme Wording)

  • Electrolysis: the decomposition of an ionic compound using electricity
  • Cathode: the negative electrode where reduction (gain of electrons) occurs
  • Anode: the positive electrode where oxidation (loss of electrons) occurs
  • Electrolyte: a substance that conducts electricity when molten or dissolved in water

Recurring Mark Scheme Answers

  • negative electrode: potassium positive electrode: chlorine observations: (yellow-) green vapour
  • anode (left) AND cathode (right) correctly labelled leads connected correctly to electrodes test-tubes over both electrodes and dipping into electrolyte
  • positive electrode: chlorine negative electrode: magnesium
  • positive electrode: iodine negative electrode: sodium
  • left hand electrode labelled anode electrolyte labelled
  • negative electrode: lead positive electrode: bromine
  • anode (on right) and cathode (on left) power supply added AND connecting wire from each end of power supply to separate electrodes
  • positive electrode: bromine / Br2 negative electrode: magnesium / Mg

Common Question Types

  • Extended writing (describe/explain/suggest): “Explain why copper is produced at the cathode when aqueous copper sulfate is electrolysed”
  • Diagram/labelling task: “Label the anode, cathode, and electrolyte on the diagram”
  • Short recall (state/give/name): “State the product at the anode when concentrated NaCl(aq) is electrolysed”
  • Half-equation writing: “Write the half-equation for the anode reaction”

Exam Tips

  • This topic appears in 26 papers in the database
  • Total Q+A entries: 41
  • Average marks per question: 1.7
  • The most common error is confusing molten and aqueous electrolysis — read the question carefully for “molten” vs “aqueous”
  • Always write half-equations with the correct number of electrons — check the charge balances
  • For diagrams, anode is on the LEFT (connected to positive terminal) and cathode on the RIGHT (connected to negative terminal) in standard IGCSE diagrams — check past paper conventions
  • The O2 half-equation (4OH- → O2 + 2H2O + 4e-) is the most frequently tested half-equation in this topic

Keywords from Past Papers

electrode, labelled, negative, positive, anode, cathode, correctly, electrolyte, chlorine, bromine, magnesium, observations, left, electrodes, power



Sources

Past Paper Sources

  • 0620/32 Feb/March 2017: Q22(a)(ii) (1m)
  • 0620/32 Feb/March 2018: Q55(a)(i) (1m)
  • 0620/32 Feb/March 2019: Q66(a)(ii) (2m), Q66(d)(i) (2m)
  • 0620/32 Feb/March 2020: Q77(a)(i) (3m), Q77(a)(i) (2m)
  • 0620/32 Feb/March 2021: Q77(b)(ii) (1m)
  • 0620/32 Feb/March 2022: Q66(c)(iii) (2m)
  • 0620/32 Feb/March 2023: Q55(b)(i) (2m), Q55(b)(ii) (1m)
  • 0620/32 May/June 2018: Q55(a)(i) (1m), Q55(a)(ii) (1m), Q55(a)(iii) (1m)
  • 0620/32 May/June 2020: Q55(a)(i) (2m), Q55(a)(ii) (2m)
  • 0620/33 May/June 2016: Q22(c)(ii) (1m)
  • 0620/33 May/June 2017: Q22(d)(i) (1m)
  • 0620/33 May/June 2022: Q33(b)(iv) (2m), Q77(b)(i) (2m), Q77(b)(ii) (2m)